Given that m and N are constants, if the solution set of inequality - mx-n > 0 is x0, what is the solution set

Given that m and N are constants, if the solution set of inequality - mx-n > 0 is x0, what is the solution set

-mx-n>0
mx-m
n

Let f (x) = MX ^ 5 + NX ^ 3-1, where m and N are constants. If f (- 2) = 8, then f (2)=

If f (- 2) = m (- 2) ^ 5 + n (- 2) ^ 3-1 = - (M2 ^ 5 + N2 ^ 3) - 1 = 8, then M2 ^ 5 + N2 ^ 3 = - 9, so f (2) = M2 ^ 5 + N2 ^ 3-1 = - 9-1 = - 10

Given (MX + n) / (x ^ 2-1) + (nx-m) / (x ^ 2-1) = (3x-1) / (x ^ 2-1), find the value of constant M, n

(mx+n)/(x^2-1)+(nx-m)/(x^2-1)=(3x-1)/(x^2-1),(mx+n+nx-m)/(x²-1)=(3x-1)/(x²-1)[x(m+n)+(n-m)]/(x²-1)=(3x-1)/(x²-1)∴m+n=3n-m=-1∴m=2n=1