Solve the equations 32x − 12Y = − 1x + 2Y + 10 = 0

Solve the equations 32x − 12Y = − 1x + 2Y + 10 = 0

The equations are arranged as follows: 3x − y = − 2, ① x + 2Y = − 10, ②, ① × 2 + ②: 7x = - 14, that is, x = - 2, substituting x = - 2 into ② to get: y = - 4, then the solution of the equations is x = − 2Y = − 4

Solving equations 3 / 2y-5 / 2x = 4 / 3 1 / y + 3 / x = 4
3/2y-5/2x=4/3
1/y+3/x=4
Need process
(2) Solving equations 4 / x + 5 / y = 0
x/x+4-y+3/y-3=0

3/2Y-5/2X=4/3
3/y-5/x=8/3
1/y+3/x=4
3/y+9/x=12
Subtraction of two formulas
9/x+5/x=12-8/3
14/x=28/3
x=14x3/28=3/2
1/y+3/(3/2)=4
1/y+2=4
1/y=2
y=1/2
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Solving the equations: x + y + Z = 3 (1) x + 2Y + 3Z = 6 (2) 2x + y + Z = 5 (3)
There should be a process. Thank you

(3)-(1):
x=2
Substituting (1) (2): 1
y+z=1 (4)
2y+3z=4 (5)
(5)-(4)*2:
z=2
Substituting (4)
y=-1