(1 / 2) factorization factors: 1. The fourth power of a - the square of 13a, the square of B + the fourth power of 36B. 2. 1 - (the square of X - 4xy) + the square of 4Y? 3 (1 / 2) factorization factors: 1. The fourth power of a - the square of 13a, the square of B + the fourth power of 36B. 2. 1 - (the square of x-4xy) + the square of 4Y? 3. (the square of X + the square of Y)-

(1 / 2) factorization factors: 1. The fourth power of a - the square of 13a, the square of B + the fourth power of 36B. 2. 1 - (the square of X - 4xy) + the square of 4Y? 3 (1 / 2) factorization factors: 1. The fourth power of a - the square of 13a, the square of B + the fourth power of 36B. 2. 1 - (the square of x-4xy) + the square of 4Y? 3. (the square of X + the square of Y)-

1、a^4-13a^2b^2+36b^4
=(a^2-4b^2)(a^2-9b^2)
=(a+2b)(a-2b)(a+3b)(a-3b)
2、1-(x^2-4xy)+4y^2
=1-x^2+4xy+4y^2
=(2y+1)^2-x^2
=(2y+x+1)(2y-x+1)
3. (x squared + y squared)-
This is not complete

Decompose the fourth power of factor x minus five times the square of x plus four

x^4-5x^2+4
=(x^2-1)(X^2-4)
=(x+1)(x-1)(x+2)(x-2)

Let a = {- 2,3}, B = {x | x ^ 2-2ax + B = 0}, if B ≠ an empty set and B contains a, find the value of a and B

If you follow the meaning of your question, it will be simple
B contains a because there are two elements in a and at most two elements in B
Then B = a
So the two roots of X & # 178; - 2aX + B = 0 are - 2,3
So 3 + (- 2) = 2A
3*(-2)=b
So a = 1 / 2, B = - 6