Extracting common factors （1）5y^3-20y^2 (2)a^2 x^2 y --axy^2 (3)6a^2b-4a^3b^3-2ab (4)4a^2-12a^3 (5)-4m^3+16m^2-6m (6)3(x+1)-(x+1)^2 (7)3(x-y)-2(x-y)^2 (8)5m(a+b)-a-b Also, I don't understand this very well. Please don't understand it on Baidu. I can't understand it, in my own words

Extracting common factors （1）5y^3-20y^2 (2)a^2 x^2 y --axy^2 (3)6a^2b-4a^3b^3-2ab (4)4a^2-12a^3 (5)-4m^3+16m^2-6m (6)3(x+1)-(x+1)^2 (7)3(x-y)-2(x-y)^2 (8)5m(a+b)-a-b Also, I don't understand this very well. Please don't understand it on Baidu. I can't understand it, in my own words

（1）5y^3-20y^2
The common factor of this problem is 5Y & # 178;, after extracting the common factor, the original formula is only: (y-4),; so the original formula = 5Y & # 178; (y-4)
(2)a^2 x^2 y --axy^2
The common factor of this formula is ax. After extraction, the original formula remains: (ax-y). Therefore, the original formula = ax (ax-y)
(3)6a^2b-4a^3b^3-2ab
The common factor of this formula is 2Ab. After extraction, the original formula remains: (3a-2a & # 178; B & # 178; - 1). Therefore, the original formula = 2Ab (3a-2a & # 178; B & # 178; - 1)
(4)4a^2-12a^3
The common factor of this formula is 4A & # 178;, after extraction, the original formula remains: (1-3a), therefore, the original formula = 4A & # 178; (1-3a)
(5)-4m^3+16m^2-6m
The common factor of this formula is - 2m; after extraction, the original formula remains: (M & # 178; - 8m + 3), so the original formula = - 2m (M & # 178; - 8m + 3)
(6)3(x+1)-(x+1)^2
The common factor of this formula is (x + 1); after extraction, the original formula remains: [3 - (x + 1)] = (3-x-1) = (2-x), so the original formula = (x + 1) (2-x)
(7)3(x-y)-2(x-y)^2
The common factor of this formula is (X-Y). After extraction, the original formula remains: [3-2 (X-Y)] = (3-2x + 2Y). Therefore, the original formula = (X-Y) (3-2x + 2Y)
(8)5m(a+b)-a-b=5m(a+b)-(a+b)
The common factor of this formula is (a + b). After extraction, the original formula remains: (5m-1). Therefore, the original formula = (a + b) (5m-1)

(1) The third power of 9m + the square of 27m = () (M + 3)
(2) Decomposition factor: 8 / 9 a square B to the power of N + 1 - 4 / 3 AB to the power of N + 1 - 2 / 3 AB to the power of n
(3) Decomposition factor: m power of a - M + 2 power of a + 3M power of a

"Mathematical answer group" for you to answer, I hope to help you
(1) The third power of 9m + the square of 27m = (9m & # 178;) (M + 3)
(2) Decomposition factor: 8 / 9 a square B to the power of N + 1 - 4 / 3 AB to the power of N + 1 - 2 / 3 AB to the power of n
=The nth power of 2 / 3 AB (4 / 3 ab - 2B - 1)
(3) Decomposition factor: m power of a - M + 2 power of a + 3M power of a
=M power of a (2 power of 1-A + 2m power of a)
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Tigong factor method (urgent!
How to calculate (x + y + Z) (X-Y + Z) + (Y-X + Z) (y-x-z) and a (a-b-c) + B (C-A + b) + C (B-A + C) by common factor method?

The first one regards (x + Z) as a whole (Y-X) as a whole
a(a-b-c)+b(c-a+b)+c(b-a+c)
=a(a-b-c)-b(a-b-c)-c(a-b-c)
=(a-b-c)(a-b-c)
=The square of (a-b-c)
If X-Y is greater than Z, what you do is wrong