How to extract the common factor from the square of x plus the square of X multiplied by the square of x plus the product of x minus 2 minus 3 (x2+x)(x2+x-2)-3

How to extract the common factor from the square of x plus the square of X multiplied by the square of x plus the product of x minus 2 minus 3 (x2+x)(x2+x-2)-3

(x²+x)(x²+x-2)-3
=(x²+x)²-2(x²+x)-3
=(x²+x-3)(x²+x+1)

One minus 2 / x plus 1 / 2 of X is equal to 0. Ask for the help of the great God for the cube of 1 / X

1 - (2 / x) + (1 / x) = 0, so x ≠ 0, so both sides of the equation multiply x at the same time to get: x-2x + 1 = 0, so (x-1) = 0, so x = 1, so the cube of (1 / x) = 1

(x + 3) (X-2) = - 6 how to calculate the addition process with the decomposition common factor method

x2+3x-2x-6=6
x2+x=0
x(x+1)=0
x=0 x=-1

40 (1 + x) ^ 2 = 48.4 calculated by decomposition common factor

（1+x）^2=1.21
1+x=1.1
x=0.1