Factorization: 4x quartic - 65x square y square + 16y quartic

Factorization: 4x quartic - 65x square y square + 16y quartic

4X quartic - 65x square y square + 16y quartic
4 -1
1 -16
Original = (4x & # 178; - Y & # 178;) (X & # 178; - 16y & # 178;)
=（2x+y）（2x-y）（x-4y）（x+4y）

The second power of 7Y [x-3y] - the third power factorization of 2 [3y-x]
100 more for correct answer

The second power of 7Y [x-3y] - the third power of 2 [3y-x] = the second power of 7Y [x-3y] + the third power of 2 [x-3y]
=[x-3y] ^ 2 [y + 2x] got it?

Factorization: x ^ 2-4xy + 3Y ^ 2-x-y-2

x²-4xy+3y²-x-y-2
=(X-Y) (x-3y) - (x + y) - 2 and then cross multiply
(x-y) + 1
(x-3y) - 2
—————————
+(x-3y) -2(x-y)=-(x+y)
Original formula = (X-Y + 1) (x-3y-2)