(a + B + C) (a square + b square + C square - AB AC BC) + 3ABC

(a + B + C) (a square + b square + C square - AB AC BC) + 3ABC

(a+b+c)(a^2+b^2+c^2-ab-ac-bc) +3abc =(a+b+c)(a^2+b^2+2ab-ac-bc+c^2)-3ab(a+b+c) +3abc =(a+b+c)[(a+b)^2-(a+b)c+c^2]-3ab(a+b+c) +3abc =[(a+b)^3+c^3]-(3a^2b+3ab^2+3abc)+3abc =[( a+b)^3-3a^2b-3ab^2]+c^3-3abc+3abc =a^3+b^3+c^3

Decompose the quadratic power of a, the square of b-ab + the square of a, the square of c-AC - 3ABC + the square of B, the square of C + BC

a^2b-ab^2+a^2c-ac^2-3abc+b^2c+bc^2=(a^2b-ab^2-abc)+(a^2c-ac^2-abc)+(b^2c+bc^2-abc)=ab(a-b-c)+ac(a-c-b)+bc(b+c-a)=ab(a-b-c)+ac(a-b-c)-bc(a-b-c)=(ab+ac-bc)(a-b-c)

Factorization 1, a square - AB AC + BC 2, a square - b square - C square + 2BC 3, x square - 1-4y-4y square 4, x square - y square - 2x-4y-3
Super urgent,

1. A square - AB AC + BC = a (a-b) - C (a-b) = (a-b) (A-C) 2, a square - b square - C square + 2BC = A & # 178; - (B-C) & # 178; = (a + B-C) (a-b + C) 3, X Square - 1-4y-4y square = x & # 178; - (2Y + 1) & # 178; = (x + 2Y + 1) (x-2y-1) 4, x square - y square - 2x-4y-3 = x & # 178; - 2x + 1 - (...)