Judge whether the value of the following unknowns is the root of the equation 2x square + X-1 = 0: X1 = - 1, X2 = 1, X3 = 1 / 2

Judge whether the value of the following unknowns is the root of the equation 2x square + X-1 = 0: X1 = - 1, X2 = 1, X3 = 1 / 2

We can substitute these numbers into the original equation to see if they are tenable
X1 = - 1 yes, the other two are not

Factorization 1,2x-5x-3 2,12x-50x + 8 3, - 20x + 9x + 20 4,4a-6a + 25,4y + 4y-56,3ax-6ax
Try to answer all the questions

1,2x-5x-3 = (2x-1) (x + 3) 2,12x-50x + 8 = (12x-2) (x-4) 3, - 20x-9x + 20 = (5x + 4) (- 4x + 5) 4,4a-6a + 2 = (4a-2) (A-1) 5,4y-5y = (2Y + 1) & # 178; - 6 = (2Y + 1 + √ 6) (2Y + 1 - √ 6) 6,3ax-6ax = 3ax (X-2)

Factorization: (1) a ^ 2-4b ^ 2 + 3a-6b (2) 4m ^ 2-4m + 2n-n ^ 2

a^2-4b^2+3a-6b
=(a-2b)(a+2b)+3(a-2b)
=(a-2b)(a+2b+3)
4m^2-4m+2n-n^2
=4m^2-n^2-(4m-2n)
=(2m-n)(2m+b)-2(2m-n)
=(2m-n)(2m+b-2)

1.4m-m(3a-2)^2
2.9-6y^3+y^6
3.x^3-x^2-2x+2

1.4m-m(3a-2)^2=m(4-4+12a-9a^2)=3ma(4-3a)
2.9-6y^3+y^6=(y-3)^2
3. X ^ 3-x ^ 2-2x + 2 = x ^ 2 (x-1) - 2 (x-1) = (x ^ 2-2) (x-1) = (x + root 2) (x-root 2) (x-1)