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How to solve the square factorization of X-1 / 2-x-2 / 3 = x
X ^ 2-1 / 2-x-2 / 3 = factorization of x ^ 2
The results are as follows
6x^2-3-6x-4-6x^2==0
-6x==7
x==-7/6
The square of (x + 4) = 5 (x + 4) is solved by factorization
Square of (x + 4) = 5 (x + 4)
(x+4)^2-5(x+4)=0
(x+4)(x+4-5)=0
(x+4)(x-1)=0
X = - 4 or x = 1
Using factorization (2x + 3) ^ 2 = 24x
4x^2+12x+9-24x=0
4x^2-12x+9=0
(2x-3)^2=0
x=1.5
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