Solving the equation x2 + 2aX + A2 = 1 about X

x²+2ax+a²-1=0
x²+2ax+(a+1)(a-1)=0
1 a+1
×
1 a-1
(x+a+1)(x+a-1)=0
x=-a-1,x=-a+1

x2-2ax+a2=x-a

X2-2ax + A2 = x-a becomes (x-a) ^ 2 = x-a, so (x-a) (x-a-1) = 0, so x = a or x = a + 1

Factorization: (x ^ 2 + X + 1) (x ^ 2 + X + 2) - 12,

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