Let Z satisfy the module of (2Z + 15) = the module of radical 3 * (conjugate of Z + 10) RT, Finding the module of Z Read the question carefully The answer in an hour is added. 10 Expiration is invalid Module of (2Z + 15) = radical 3 * [(conjugate of Z + 10)]

Let Z satisfy the module of (2Z + 15) = the module of radical 3 * (conjugate of Z + 10) RT, Finding the module of Z Read the question carefully The answer in an hour is added. 10 Expiration is invalid Module of (2Z + 15) = radical 3 * [(conjugate of Z + 10)]

Let Z satisfy the absolute value of 2Z + 15 = the root sign 3 times the absolute value of conjugate + 10 of Z, and find the Mo value of Z

Let z = a + bi
The conjugate of / 2Z + 15 / = (2a + 15) ^ 2 + 4B ^ 2 / Z + 10 / = √ (a + 10) ^ 2 + B ^ 2
The conjugate of ∵ / 2Z + 15 / = √ 3 / Z + 10/
Two sides square
（2a+15)^2+4b^2=3[(a+10)^2+b^2]
It is reduced to a ^ 2 + B ^ 2 = 75
And / Z / = √ (a ^ 2 + B ^ 2) = √ 75 = 5 √ 3

Let Z satisfy Z + 4Z = a (where a is a real number). (1) find | Z |; (2) if | Z-2 | = 2, find the value of A

Let z = x + y (x, y ∈ R and Y ≠ 0) (2) then Z + 4Z = 4Z + 4Z = x + 4Z = x + 4Z + 4x {+ 4x {4x {4x} 4yix2 + y2 = a ∈ R (x, y, y, y, y ∈ R (x, y, y ∈ R (x, y, y ∈ R, y ∈ R, and Y ∈ R and Y ∈ R and y-2-2-2-2-2-2-2-2 + y2 = 2) is (X-2) 2) 2 + 2 (X-2) 2 + 2 = 2, and X2 + y2 = 4 (y = 2 = 4 (y = 2 + y = 2 = 4 (y = 4 (y = 2 + y = 2 = 4) (y = 2) (y = 2) (y = 2 + y = 2) (y = 2 + y \a = Z + 4Z = 2 & nbsp; & nbsp; (12 points)