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A (cos23, cos67) B (cos68, cos22) finding the vector product of ab
a*b=cos23*cos68+cos67*cos22
=cos23*sin22+sin23*cos22
=sin(22+23)
=sin45
=1
The direction of vector product
If the vector module length of the vector product is 0, then it is a 0 vector. But at this time, can its direction be arbitrary? Can its direction be determined by the algorithm of cross product?
Or at this time, we still don't set the direction, let it's direction or arbitrary?
Let C = a × B | C | = | a | * | B | * sin. If a and B are both non-zero vectors, then when = 0 or π, that is, when a and B are in the same direction or opposite direction, the direction of the vector obtained from the outer product of | C | = 02 vector is perpendicular to the plane of the two vectors
I'm in high school now. I'm good at math, so I know more, but it doesn't seem to be very good,
I've seen three explanations for the product of vectors
1. Scalar product, module multiplication and cosine of angle
2. Module multiplication and phase addition
3. What cross product, module multiplication, and then angle sine multiplication
So, how should the product of two vectors be expressed?
What are the above three situations?
Also, if it's OK, score
If a question says the product of two vectors, which is the default?
The math teacher said that if a vector is multiplied by a vector, it must get a number. Isn't that right
1. Let a = [A1, A2,... An] and B = [B1, B2... BN], then the inner product of a and B can be calculated in two ways: a · B = A1 × B1 + A2 × B2 + The results show that: a | a | B | cos θ, where | a | = (A1 ^ 2
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