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Let f (x) be an odd function whose domain of definition is r, and increase in the interval (0, + ∞). If f (- 2) = 0, then the solution set of inequality f (x) > 0 is____
x> Increasing function
Then X0
f(2)=-f(-2)=0
So x > 2
xf(-2)
-2
Reduction formula: | a-c | - | A-B | + | 2A|
Note: b > 0 > a > C
Because b > 0 > a > C
So a-c > 0
a-b
Simplification │ 2-3b │ - 2 │ 2 + B │ + A-2 │ - 3b-2a
B is less than - 2, more than - 3, a is more than 0, less than 1
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