If the function f (1 / 2 + x) + (1 / 2-x) = 2 holds, then f (1 / 2010) + F (2 / 2010) +f（2009/2010)=?

f(1/2010) + f（2009/2010) = 2f(2/2010) + f（2008/2010) = 2f(3/2010) + f（2007/2010) = 2…… F (1004 / 2010) + F (1006 / 2010) = 2F (1005 / 2010) + F (1005 / 2010) = 2, so the result is 2009

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