![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Solving inequality system: {4x-35 - [(1 / 2) x]
solution
4x-310+2
4x>12
x>3
∴x>3
It is known that x = 2a-1 / 8 is a solution of inequality 2x-7 / 3-4x-5 / 2 + 1 ≥ 0, and the value range of a is obtained
A:
2A - (1 / 8) is a solution of inequality (2x-7) / 3 - (4x-5) / 2 + 1 > = 0
Multiply both sides by 6
2(2x-7)-3(4x-5)+6>=0
4x-14-12x+15+6>=0
-8x+7>=0
8x
On the solution of inequality - (2x + 1) / 31 of X, then the value range of a is
The system of inequalities of the first grade
-(2x+1)/30
x>-1/2
(4x+a)/5>1
4x+a>5
x>(5-a)/4
So (5-a) / 4 ≤ - 1 / 2
5-a≤-2
a≥7
RELATED INFORMATIONS
- 1. Given that f (x) is an odd function defined on R, and f (x) = f (1-x), then f (2011) = how to do this problem? Detailed process, the most important is how to find the period
- 2. The absolute value of solving equation x minus 5 = 4 The absolute value of the difference between the square of solution equation x minus 5 = 4, how to solve it
- 3. If the absolute value of X-2 is 2-x, what is the relationship between X and 2? Is 2 ≥ x?
- 4. "Given that the absolute value of a + 4 and B-3 are opposite numbers, then a + 3B=_______ "Thank you,
- 5. Given the function f (x) = 3x-2 / 2x-1, find 1: F (1 / 2009) = f (2 / 2009) +. F (2008 / 2009) (2) known sequence {an} satisfies A1 = 2, an + 1 = f (an) find the general term formula of sequence an (3) prove: a1a2a3... An > Geng Hao 2n + 1
- 6. If the function f (1 / 2 + x) + (1 / 2-x) = 2 holds, then f (1 / 2010) + F (2 / 2010) +f（2009/2010)=?
- 7. If the function f (x) is monotone in [M, n], then the difference between the maximum and minimum value of function f (x) in [M, n] is ()
- 8. The minimum and maximum of the function f (x) = 3 / x, X ∈ [- 1,2] are
- 9. If the definition field of function f (x) is {XLX ＞ 0}, and f (x) is an increasing function, f (x · y) = f (x) + F (y). F (3) = 1 And f (a) > F (A-1) + 2
- 10. If f (x) = K-2 ^ X / 1 + K2 ^ x (k is a constant) is an odd function in the domain of definition, then k =? The answer is 1 or - 1,
- 11. Along the slope of 1000m long and 250m high, a mine car weighing 6 times 10 cubic n is driven from the slope at the speed of 2m per second If the pulling force is 2 times the third power of 10, find the time from the bottom of the slope to the top of the slope; (2) the work done by Larry; (3) the work done by pulling force
- 12. The second power of (- 2 times the third power of 10)=
- 13. The fourth power of a + the square of 4A + 1 = 0 to find the process of ① a square + the square of a, ② a fourth power + the fourth power of a, ③ a octave + the eighth power of A
- 14. Let the 3x-1 power of inequality 2 be greater than 2, and the value of X is?
- 15. Solution to inequality: (number shape combination) x & # 178; - 6x + 9 ≤ 0 Is it less than or equal to zero or less than or equal to zero?
- 16. Solution set of inequality 3-10x-8x & # 178; > 0
- 17. Proving inequality with mean value theorem X > 3-1 / X (x > 0)
- 18. The monotone increasing interval of function f (x) = xlnx on (0,5) is______ ．
- 19. What is the domain of the function y = lgx ^ 2? Ar B (0, positive infinity) C (negative infinity, 0) d {x | x is not equal to 0}
- 20. The period of y = TaNx + Cotx Original formula = SiNx / cosx + cosx / SiNx =(SiNx square + cosx Square) / sinxcosx =1／sinxcosx =2／sin2x So the minimum positive period is 2 pies / 2 = pies Is that right?