Let the 3x-1 power of inequality 2 be greater than 2, and the value of X is?

Let the 3x-1 power of inequality 2 be greater than 2, and the value of X is?

The 3x-1 power of 2 is greater than 2
∴3x-1＞1
3x＞2
x＞2/3

If f (x) = 1-2 / (x-th power of 2 + 1), and the inequality f (K-2) + F (1 + x-th power of 2 + x-th power of 4) is greater than 0, the value of K is obtained for any x constant

∵ f (- x) = (1-2 ^ x) / (2 ^ x + 1) = 2 / (2 ^ x + 1) - 1 = - f (x) ∵ f (x) is an odd function and 2 ^ x monotonically increases, so 2 / (2 ^ x + 1) monotonically decreases, f (x) monotonically increases and f [2 ^ (1 + x) + 4 ^ x] > - f (K-2) = f (2-k), and f [2 ^ (1 + x) + 4 ^ x] = f [(2 ^ x + 1) & # 178; - 1 > 0 and f (x) ∵

How to solve inequality 9 to the x power + 2 times 3 to the X + 1 power - 16 greater than 0

(3^x)²+2×3×3^x-16>0(3^x)²+6×3^x-16>0(3^x-2)(3^x+8)>0∵3^x+8>0∴3^x-2>03^x>2x>log₃ 2