When x tends to 0, (1 + SiNx) ^ (1 / 3) - 1 is equivalent to
When x tends to 0, SiNx tends to 0, so (1 + SiNx) ^ (1 / 3) - 1 = 0
Why is SiNx / X equal to 1 when x tends to 0
Is the limit equal to one
The denominator of the limit molecule can be derived at the same time according to the law of Robida
lim(x→0)sinx/x=lim(x→0)(sinx)'/x'=lim(x→0)cosx=1
Finding the differential of function y = xsin2x
dy=(sin2x+2xcos2x)dx