Y = 1 / x + 2 √ x, y = xsin2x, y = x (flat) Find the differential of the function y=1/x+2√x y=xsin2x Y = x (square) e (2x Square)

Y = 1 / x + 2 √ x, y = xsin2x, y = x (flat) Find the differential of the function y=1/x+2√x y=xsin2x Y = x (square) e (2x Square)

y=1/x+2√x
dy=-1/(x^2)dx+1/√x dx=(-1/(x^2)+1/√x )dx
y=xsin2x
dy=dxsin2x+2xcosxdx=(sin2x+2xcosx)dx
Y = x (squared) e (2x squared) is the expression here clearer?

Find the derivative and differential of the function y = E & sup3; xsin2x? Note: the combination of X in front of sin and 3 is 3x, which is above E

y'=(e³x)'*sin2x+e³x(sin2x)'=e³sin2x+2e³xcos2x
dy=(e³sin2x+2e³xcos2x)dx

1.y=ln(1-x) 2.y=(e^x)sinx 3.y=(e^x)+sinx 4.y=lnsin(3x) 5.y=e^(-x)cos(3-x)

1)dy/dx=-1/(1-x)
2)dy/dx=e^x(sinx+cosx)
3)dy/dx=e^x+cosx
4)dy/dx=3cos(3x)/sin(3x)
5)dy/dx=-e^(-x)cos(3-x) +e^(-x)sin(3-x)