If x + 4 / 3 = y + 3 / 2 + Z + 8 / 4, and X + y + Z = 12, find the value of X, y, Z

If x + 4 / 3 = y + 3 / 2 + Z + 8 / 4, and X + y + Z = 12, find the value of X, y, Z


Let k = x + 4 / 3 = y + 3 / 2 + Z = 8 / 4
x+4=3k
y+3=2k
z+8=4k
therefore
x=3k-4
y=2k-3
z=4k-8
x+y+z=12
3k-4+2k-3+4k-8=12
9k=27
k=3
x=3k-4=5
y=2k-3=3
z=4k-8=4



If 3 / x + 4 = 2 / y + 3 = 4 / Z + 8, x + y + Z = 12, what is the value of X, y, Z?


Let 3 / x + 4 = 2 / y + 3 = 4 / Z + 8 = K
3=k(x+4) 3=kx+4k (1)
2=k(y+3) 2=ky+3k (2)
4=k(z+8) 4=kz+8k (3)
(1)+(2)+(3)
k(x+y+z)+4k+3k+8k=9
12k+4k+3k+8k=9
27k=9
k=1/3
Substituting (1) (2) (3) respectively
x=5
y=3
z=4
x



Then Z + 2 / y = 4, and Z + 3 / y = 4
A2
B﹣2
C﹣4
D4


X = 5, y = 3, z = 4, the result is equal to - 2, if you choose B, you will get points