The function y = f (x + 8) is even, ∴f(-x+8)=f(x+8), X = 8 is the symmetry axis of the image of the function y = f (x), Why can we see from F (- x + 8) = f (x + 8) that x = 8 is the axis of symmetry? If y = (x + 4) is an even function, can we say that the axis of symmetry is x = 4

The function y = f (x + 8) is even, ∴f(-x+8)=f(x+8), X = 8 is the symmetry axis of the image of the function y = f (x), Why can we see from F (- x + 8) = f (x + 8) that x = 8 is the axis of symmetry? If y = (x + 4) is an even function, can we say that the axis of symmetry is x = 4

It's very simple when y = x + 4
F(Y)=f(X+4)
F(-Y)=f(-X+4)
The axis of symmetry is x = (x + 4-x + 4) / 2 = 4

What is the equation of the axis of symmetry of the graph with the function y = sin (2x + open / 3)?

And the answer

Given A-B / A + B = - 3, then the algebraic formula 2 (a-b) / A + B-5 (a + b) / A-B =?

(a-b)/(a+b)=-3
(a+b)(a-b)=-1/3
2(a-b)/(a+b)-5(a+b)/(a-b)
=2×(-3)-5×(-1/3)
=-6+5/3
=-13/3