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(2x-1)/5+(3y-2)/4=2 (3x+1)/3-(3y+2)/4=3/4
(2x-1)/5+(3y-2)/4=2 ①
(3x+1)/3-(3y+2)/4=3/4 ②
① 4 (2x-1) + 5 (3y-2) = 40, that is, 8x + 15y = 54 (3)
② 4 (3x + 1) - 3 (3Y + 2) = 9, that is, 12x-9y = 11 (4)
③ 63y = 140
y=20/9
Substituting y = 20 / 9 into 4, we get 12x-20 = 11
12x=31
x=31/12
∴x=31/12
y=20/9
To find the monotone increasing interval of the function y = 3x + 2x Λ 2 + 1,
Is the middle double root X or root 2x
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