Given that y = - 1 is the solution of the equation 2-1 / 3 (M-Y) = 2Y, then the solution of the equation x + 4 = m (2x + 4) about X is

Given that y = - 1 is the solution of the equation 2-1 / 3 (M-Y) = 2Y, then the solution of the equation x + 4 = m (2x + 4) about X is

Y = - 1 is the solution of the equation 2-1 / 3 (M-Y) = 2Y
2-1/3(m-(-1))=2(-1)
-1/3(m+1)=-4
m+1=12
m=11
x+4=m(2x+4)
x+4=11(2x+4)
x+4=22x+44
21x=-40
x=-40/21

If the solutions of the equations x + y = 3, x-2y = A-3 satisfy x > 0, Y > 0, try to find the value range of A
All I know about this problem is to work out X and Y first,
We can calculate x = 3-y from the first formula,
And then we take x to the second equation,
3-y-2y = A-3
Then ask how to simplify y, and then how to find it?
(or is there a better way

x+y=3,
x> 0, so x = 3-y > 0
Get y

If the solution of the equations X-Y = 3, YZ = 4, Z + X -- 3 is also the solution of the equation mx-2y + Z = 0, then the value of M is
A. Seven out of two
B. Minus two thirds
C. Three in two
D. Minus 7 / 2

B