Given that (A-1) x ^ 2Y ^ A + 1 is the quintic monomial of X and y, (1) a ^ 2 + 2A + 1 (2) (a + 1) ^ 2, what do you think

Given that (A-1) x ^ 2Y ^ A + 1 is the quintic monomial of X and y, (1) a ^ 2 + 2A + 1 (2) (a + 1) ^ 2, what do you think

(A-1) x ^ 2Y ^ A + 1 is the quintic monomial of X and y
∴2+a+1=5
a=2
a^2+2a+1 =9
(a+1)^2=9
∴a^2+2a+1=（a+1)^2

It is known that (A-2) x ^ 2 times y ^ (a + 1) is the quintic monomial of X and y, and the value of a is obtained

(A-2) x ^ 2Y ^ (a + 1) is a quintic monomial. If x index is 2, then y index is 5-2 = 3
a+1=3
a=2

Given that (A-1) x ^ 2Y ^ A + 1 is a quintic monomial of X and y, how much is the value of (a + b) ^ 2? Urgent!

Where is B? The quintic formula is 2 + a = 5, and a = 3. Because it is a monomial formula, there is only B
The sum of the remaining items of (A-1) x ^ 2Y ^ A is zero if + 1 is followed by + B
That's B + 1 = 0, B can be calculated, and the following formula will get the result