When a takes what value, the solution of the equation 3x-5 = AX-1 is a positive integer Pro, do me a favor

When a takes what value, the solution of the equation 3x-5 = AX-1 is a positive integer Pro, do me a favor

3x-5=ax-1
(3-a)x=4
X = 4 / (3-A) is a positive integer
So 3-A is a divisor of 4
So 3-A = 1, 2, 4
So a = 2, a = 1, a = - 1

Solve the following equation about X: (1) ax + B = C (a ≠ 0) (2) mx-2 = 3x + n (m ≠ 3)

ax+b=c(a≠0)
ax=c-b
x=(c-b)/a
(2)mx-2=3x+n(m≠3）
(m-3)x=2+n
x=(2+n)/(m-3)

Solve the following equation about X: (1) ax + B = C (a ≠ 0) (2) mx-2 = 3x + n (m ≠ 3)

[solution] (1) ax + B = C (a ≠ 0)
ax=c-b
x=(c-b)/a
（2）mx-2=3x+n(m≠3)
(m+3)x=n+2
x=(n+2)/(m+3)