The solution of the equation 3x + m-2 (M + 2) = 3M + X of X is less than 5, and the value of the largest integer m that meets the requirements is obtained

The solution of the equation 3x + m-2 (M + 2) = 3M + X of X is less than 5, and the value of the largest integer m that meets the requirements is obtained

3x+m-2(m+2)=3m+x
x=2m－2＜5
m＜3.5
M is 3

①√3x(x-1)-√2(x-1)=0 ②(x-6)^2=6-x ③4(x-1)^2=25(x+1)^2 ④√2x(x+1)=x+1 ⑤x^2-9=1/2(x^2-6x+9)
Given that x is a positive number, and a = x ^ 2-16, B = 2x-8, try to compare the size of a and B
I have to hand it in at 3:00,

Comparison of size is often done by subtraction or division
A-B=X²-2X-8=(X-1)²-9
When (x-1) & sup2; - 9 = 0, that is, x = 4, a = B
When (x-1) & sup2; - 9