It is known that one root of the equation 3x ^ 3 + kx-6 = 0 of X is 2. Let the other root of the equation be x1, then there is: A.x1=3/5,k=-7 B.x1=-3/5,k=-7 C.x1=-3/5,k=7 D.x1=3/5,k=7 It is known that one root of the equation 3x ^ 2 + kx-6 = 0 of X is 2. Let the other root of the equation be x1, then there is: It's Square. Wrong number

It is known that one root of the equation 3x ^ 3 + kx-6 = 0 of X is 2. Let the other root of the equation be x1, then there is: A.x1=3/5,k=-7 B.x1=-3/5,k=-7 C.x1=-3/5,k=7 D.x1=3/5,k=7 It is known that one root of the equation 3x ^ 2 + kx-6 = 0 of X is 2. Let the other root of the equation be x1, then there is: It's Square. Wrong number

A root of 3x ^ 3 + kx-6 = 0 is 2
3*2^3+2k-6=0
k=-9
3x^3-9x-6=3(x-2)(x+1)^2=0
The other root of the equation is X1 = - 1
Wrong question
One root of the equation 3x ^ 2 + kx-6 = 0 is 2, which is substituted into the original equation
3*2^2+2k-6=0
k=-3
3x^2-3x-6=0,
The solution is as follows
The other X1 = - 1

On the equation 3x ^ 2-kx = 2-k of X, if the root is negative 2, then 2-k

The original solution = - 12 + 2K = 2-k
2K+K=2+12
3K=14
K=14/3
Then 2-k = 6 / 3-14-3 = - 8 / 3

One and a half * four ninths of a minute

Two thirds!