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Calculation: 1 + 2-3 + 4 + 5-6 + 7 + 8-9 + +97+98-99+100=______ ．
1+2-3+4+5-6+7+8-9+… +97+98-99+100=5050-3×（1+2+3… +33）×2=5050-33×342×6=1684．
I would like to ask two math problems, urgent drop ah, thank you ~!
1. In a factory, the ratio of a to B is 3:4, and the ratio of B to C is 2:3. If B produces 945 pieces less than the sum of a and C, how many pieces do each worker produce?
2. A factory newly recruited 22 technical workers to produce screws and nuts. It is known that each person produces an average of 1200 screws or 2000 nuts per day, and one screw is matched with two nuts. In order to make the products produced every day just match, how many technical workers should be assigned to produce screws and how many technical workers should produce nuts?
Please use the equation to solve, thank you
1. The ratio of a, B and C is 3:4:6. Suppose that a produces 3x pieces, B produces 4x pieces, C produces 6x pieces, then (3x + 6x) - 4x = 945, x = 189, then a produces 189 * 3 = 567 pieces, B produces 189 * 4 = 756 pieces, C produces 189 * 6 = 1134 pieces
2. If x skilled workers are assigned to produce screws, then (22-x) skilled workers are assigned to produce nuts
1200X=1/2*2000*(22-X)
X=10
22-10 = 12 people,
We should assign 10 technicians to produce screws and 12 technicians to produce nuts
Zero minus two and two fifths minus eight plus thirteen and four fifths minus six and one fifths
0.25 plus minus one quarter plus minus three and one eighth plus minus five and three fourths
1 original formula = 0-2 and 2 / 5-8 + 13 and 4 / 5-6 and 1 / 5 = (- 2 and 2 / 5) + (- 8) + 13 and 4 / 5 + (- 6 and 1 / 5) = [(- 2 and 2 / 5) + (- 8) + (- 6 and 1 / 5)] + 13 and 4 / 5 = [- (2 and 2 / 5) + 8 + 6 and 1 / 5)] + 13 and 4 / 5 = (- 16 and 3 / 5) + 13 and 4 / 5 = - (16 and 3 / 5-13 and 4 / 5) = - 2 and 4 / 52 original formula = 0
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