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Who will give points to math problems! （ ）：6=0.75 3 △ 5 = 9: () = 20 parts () = () [fill in decimal]
(9 / 2): 6 = 0.753 △ 5 = 9: (15) = 12 / 20) = (0.6) & nbsp; & nbsp; & nbsp; & nbsp; ~ 523 answers for you all the time. I wish you progress in your study ~ ~ ~ if you agree with my answer, please click the [adopt as satisfactory answer] button in time ~ ~ the mobile phone questioner can comment "satisfied" in the upper right corner of the client. ~ your adoption is my driving force ~ ~ ~ if there are any new questions, Please ask me for help. The answer is not easy. Please understand~~
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Wudalang's sweet and salty pancakes are sold fast in the streets; sweet three salty 22% 1, salty four salty 22% 2; how to sell Wudalang's Pancakes if you buy one sweet and salty pancake each?
Eight armed and one headed Yaksha, three headed and six armed are Nezha. They fight for victory in two places, and win or lose in two places. There are thirty-six gods of Qisi, one hundred and eight hands, and how many Nezha and Yaksha?
1. Set the price of sweet cake as X% and salty cake as y%,
Then there is 3x + 2Y = 2.1 （1）
2x+4y=2,2……………… （2）
（1）-（2）：x-2y=-0.1,
That is, x = 2y-0.1 （3）
Where 4y-0.2 + 4Y = 2.2,
8y=2.4,
y=0.3；
In (3), x = 0.6-0.1 = 0.5
Therefore, the price of each sweet salted cake is
X + y = 0.5 + 0.3 = 0.8 (CM)
A: one sweet salty cake for each, and Wudalang cake costs eight cents
2. There are x Nezha, y Yasha,
Then 3x + y = 36 （1）
6x+8y=108……………… （2）
（2）-（1）×2：6y=36,
y=6；
Where (1), x = 10
Answer: 10 Nezha 6 night fork
It is known that OE is the bisector of AOC and OD is the bisector of BOD
(1) If ∠ AOC = 120 ° and ∠ BOC = β, calculate ∠ doe
(2) If ∠ AOC = α, ∠ BOC = β (α is greater than β), calculate ∠ BOE
There are two situations
The first case: OB is between OA and OC
∵ OE bisection ∠ AOC
∴∠COE＝∠AOC/2＝120/2＝60
∵ od bisection ∠ BOC
∴∠COD＝∠BOC/2＝β/2
∴∠DOE＝∠COE-∠COD＝(60-β/2)°
The second case: OC is between OA and ob
∵ OE bisection ∠ AOC
∴∠COE＝∠AOC/2＝120/2＝60
∵ od bisection ∠ BOC
∴∠COD＝∠BOC/2＝β/2
∴∠DOE＝∠COE+∠COD＝(60+β/2)°
2. Solution
There are two situations
The first case: OB is between OA and OC
∵ OE bisection ∠ AOC
∴∠COE＝∠AOC/2＝a/2
∵ od bisection ∠ BOC
∴∠COD＝∠BOC/2＝b/2
∴∠DOE＝∠COE-∠COD＝a/2-b/2＝(a-b)/2
The second case: OC is between OA and ob
∵ OE bisection ∠ AOC
∴∠COE＝∠AOC/2＝a/2
∵ od bisection ∠ BOC
∴∠COD＝∠BOC/2＝b/2
∴∠DOE＝∠COE+∠COD＝a/2+b/2＝(a+b)/2
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