A problem of calculating trapezoidal area in Volume 1 of grade 5 Form a flower bed by the wall. The fence is 46m long. Calculate the area of the flower bed The height is 20 meters

A problem of calculating trapezoidal area in Volume 1 of grade 5 Form a flower bed by the wall. The fence is 46m long. Calculate the area of the flower bed The height is 20 meters


It can be seen from the figure that this is a right angled trapezoid. The height of the trapezoid is 20m, while the length of the fence around the flower bed is 46m, so the sum of the upper bottom and the lower bottom is 26m. According to the area formula of the trapezoid, (upper bottom + lower bottom) × height △ 2, the area of the trapezoid is 26 × 20 △ 2 = 260 (square meters)



The bottom area of a cylinder and a cone is equal. The volume of a cone is one sixth of that of a cylinder. The height of a cone is 4.8 cm. How many cm is the height of a cylinder?


1 / 6 divided by 1 / 3 = 1 / 2
4.8 divided by 1 / 2 = 9.6cm (height of cylinder)



If the height of the cone is 4.2 cm, the height of the cylinder is 4.2 cm______ If the height of a cylinder is 4.2 cm, the height of a cone is 1.5 cm______ Cm


According to the stem analysis, we can get: (1) 4.2 × 2 = 8.4 (CM), (2) 4.2 △ 2 = 2.1 (CM), answer: if the height of the cone is 4.2 cm, the height of the cylinder is 8.4 cm; if the height of the cylinder is 4.2 cm, the height of the cone is 2.1 cm