What is the relationship between sin1, cos1 and TAN1

What is the relationship between sin1, cos1 and TAN1

tan1>sin1>cos1
π/4sin1> cos1>√2/2
√3>tan1>1
tan1>sin1>cos1

The size relation of sin1, cos1 and TAN1 is ()
A. tan1＞sin1＞cos1B. tan1＞cos1＞sin1C. cos1＞sin1＞tan1D. sin1＞cos1＞tan1

∵ π 4 ＜ 1 ＜ π 2, ∵ TAN1 ＞ 1, cos1 ＜ sin1 ＜ 1, ∵ TAN1 ＞ sin1 ＞ cos1

The size of sin1, cos1, TAN1
How to calculate specifically?

The drawing shows that sin1 is less than TAN1 and cos1

Tana equals one third, so what's the angle a

tanA=1/3,A=atan(1/3)=18.4°

Why is Tana equal to the opposite side of angle A / Tana
Why is Tana equal to the opposite side of angle a divided by Tana

Tana = ∠ a opposite side / adjacent side. Just change its position

The size relationship between cos1 and sin1

Since SiNx is an increasing function and cosx is a decreasing function on [0, π / 2], sin1 > sin π / 4 cos1 cos1

A is 2 / 3 of B. what is the ratio of a to B?

2：3

A is twice of B, B is two thirds of C, a: B: C = ()

a:b=2:1=4:2
b:c=2:3
A:B:C=(4:2:3 )

If a × 4 / 5 = B × 2 / 3, then a: B = (): ()

A :B =A/B
=2/3 / 4/5= 5:6

If - (a-b) = 5 and two-thirds, then B-A =?

-（a-b）=b-a
So B-A = 5 and 2 / 3