Given that a is the angle of the second quadrant, what quadrant is the angle of two parts of a?

π/2+2kπ

If a is the second quadrant angle, then a / 2 is

0

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Original formula =2: the root sign of 2* (sina+cosa) / (the square of 2sinacosa+2cosa)
=2 * (Sina + COSA) / [2cosa (Sina + COSA)]
=(radical 2) / (4cosa)
Because Sina = radical 15 / 4
A is the second quadrant angle, so cosa = - 1 / 4
So the original = - radical 2

Sina = m comb = m (a + B ≠ 0) (absolute value a is not equal to absolute value b) find sin (a + b) =? Tan (a + b) =?

Sin(A+B)=1
Tan (a + b) = positive infinity
The answer is limited to 180 degrees

If Tan α = - 1 / 2, π / 2 < α < π, then sin α is equal to

tanα=-1/2,
π/2<α<π,
Then sin α > 0 and cos α < 0
sinα/cosα=-1/2
cosα=-2sinα
sin²α+cos²α=1
5sin²α=1
sin²α=1/5
sinα=√5/5

Cos (π / 6 - α) = m, the absolute value of M is less than or equal to 1, and COS (5 π / 6 + α) is calculated

cos(5π/6+α)=-cos[π-（5π/6+α)]=-cos(π/6-α)
So cos (5 π / 6 + α) = - M

If the absolute value of cos a/2 =1/5,5 π

The formula sin (A / 2) = positive and negative root sign ((1-cosa) / 2), that is sin (A / 4) = positive and negative root sign (1-cos (A / 2)) / 2
A is 5 π to 6 π, so a / 2 is 5 π / 2 to 3 π, cos A / 2 = negative 1 / 5, a / 4 is 5 π / 4 to 3 π / 2, sin a / 4 is negative, so it is - √ 15 / 5

Image of absolute value of sin α + absolute value of cos α

The image of y = ︱ Sina + ︱ cosa is:
(1) After the first and second quadrants, the left and right symmetry
(2) The value range is between [1, root 2]
(3) Period KPAI / 2
(4) A string of steamed buns
method:
[0,90 degrees] y = Sina + cosa
[90180 degrees] y = Sina - cosa
[180270 degrees] y = - Sina - cosa
[270360 degrees] y = - Sina + cosa
Then discuss it in the form of addition and subtraction root 2 * sin (a addition and subtraction of 45 degrees)

What is the interval in which the absolute value of sin is greater than that of COS, and what interval is the absolute value of COS greater than that of sin

The absolute value of SiNx is greater than that of cosx
That is, the square of SiNx is greater than that of cosx
That is cos? X - sin? X < 0
That is, cos2x

The maximum of absolute value of sin α - cos α

sinα-cosα
=√2(√2/2*sinα-√2/2cosα)
=√2(sinαcosπ/4-cosαsinπ/4)
=√2sin(α-π/4)
Therefore, the maximum value of | sin α - cos α | is = √ 2

Given that a is the angle of the second quadrant, what quadrant is the angle of two parts of a?