The inverse function of the function y = 2x is A. Y = logx2, x > 0 and X ≠ 1 B.y=log2x,x>0 C. Y = (1 / 2) x squared, x > 0 D.y=log（1/2）x,x>1

The inverse function of the function y = 2x is A. Y = logx2, x > 0 and X ≠ 1 B.y=log2x,x>0 C. Y = (1 / 2) x squared, x > 0 D.y=log（1/2）x,x>1

B.
Log (2) y = x, Y > 0 is obtained by taking the logarithm with the base of 2 on both sides

Y = 2x + 1 / 2x-1 inverse function Inverse function of 2 to the power of X

x=(2^y+1)/(2^y-1)
x*2^y-x=2^y+1
(x-1)2^y=x+1
2^y=(x+1)/(x-1)
y=log2[(x+1)/(x-1)]

Inverse function of function y = 2x-1______ .

From y = 2x-1, x = 1 + log2y and Y > 0
That is, y = 1 + log2x, x > 0
So the inverse function of the function y = 2x-1 is y = 1 + log2x (x > 0)
So the answer is: y = 1 + log2x (x > 0)

Y=2X-1（X

Let X be represented by Y: x = (y + 1) / 2
Then x and y are interchanged: y = (x + 1) / 2
Finally, find the definition domain of X, that is, the original function range: because the original X

Find the inverse function y = x ^ 2-2x + 3 (x ≤ 0) Find the inverse function y = x ^ 2-2x + 3 (x ≤ 0),

y=X^2-2X+3=（X-1）^2+2（X==3
Because x = = 3

The inverse function of the function y = 2x + 1 is______ .

∵y=2x+1
∴x+1=log2y
That is, x = log2y-1
Therefore, the inverse function of the function y = 2x + 1 is y = log2x-1
So the answer is: y = log2x-1 (x > 0)

The inverse function of Y (x) = 5x + 4

y=5x+4
5x=y-4
X = (y-4) / 5, so the inverse function is y = (x-4) / 5
Hope to help you!

Y = x ^ 3 / 5-2 inverse function

x^3/5=y+2
x^5=(y+2)^3
x=(y+2)^5/3
So the inverse function is
y=(x+2)^5/3

What is the inverse function of y = 5 ^ x

log5,y=x

How to find the inverse function of y = (1 / 2) arcsin (1-2x)

2y=arcsin(1-2x)
1-2x=sin2y
x=(1-sin2y)/2
The inverse function is y = (1-sin2x) / 2 x ∈ (- π / 4, π / 4)