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Given that the square of X - 3x + 2 is equal to 0,6x - (the square of 2x) is equal to what
From x 2 - 3x + 2 = 0, x = 2 or x = 1 can be obtained
6x-(2x)²=x(6-2x)
When x = 2, X (6-2x) = 2 × (6-2 × 2) = 4
Or x = 1, X (6-2x) = 1 × (6-2 × 1) = 4
So 6x - (2x) 2 = 4
Given that the square of 2x minus 3x + 1 is 8, find the value of the following algebraic formula: ① the square of 4x minus 6x + 5; ② two thirds of X; the square of x minus X and five thirds The sum of the square of 3x and the subtraction of 2x 6x is the sum of 2x 6x ② The square of two-thirds of x minus x plus five-thirds
2X^2-3x+1=8
The square of 4x minus 6x + 5 = 2 (2x ^ 2-3x + 1) + 3 = 8 + 2 = 10
Two thirds of X squared minus x plus five thirds = 1 / 3 (2x ^ 2-3x + 1) + 4 / 3 = 1 / 3 * 8 + 4 / 3 = 4
The square of 4A, the square of B, the square of 3x in the fifth, the square of 4x minus 3, the square of a minus 2Ab and the square of B The coefficient, frequency and item number of
0
0
The original formula = - X-2,
When x = 1
When 2, the original formula = - 1
2-2=-21
2．
Given that x squared minus 3x plus one equals zero, find the sum of X squared plus one part of x square
Divide both sides by X
x+1/x=3
x^2+1/x^2
=(x+1/x)^2-2
=7
What is the square of 5x + 3x-8?
5x^2+3x-8
=(5x+8)(x-1)
If you add 3x-5x-5, then you get a polynomial of - 3x-7 A. 4x2+5x+11 B. 4x2-5x-11 C. 4x2-5x+11 D. 4x2+5x-11
A = (5x2-3x-1) - (x2-x-7) + (- 3x + 5) = 4x2-5x + 11
Solve the following one variable quadratic equation 1, 10 + 3x-x square 2, 3x square + 5x + 1 = 0 3, 2x square = 3-7x
1. (5-4 * 3 * 1) / (2 * 3) = [- 5 ± root number (5 ^ 2-4 * 3 * 1)] / (2 * 3) = [- 5 ± root number (5 ^ 2-4 * 3 * 1)] / (2 * 3) = [- 5 ± root 13] / 6X1 = (- 5-root 13) / 6, X2 = (-5 + root 13) / 63, 2xsquare = 3-7x2x ^ 2 + 7x-3 = 3-7x2x ^ 2 + 7x-3 = 0 = [- 7 ± root (7 ^ 2 + 4 * 2 * 3)] / (2 * 2) = [- 7 ± root number 73 73 73 73 73 73 73 73 73 (2 * 2 * 2) / (2 * 2) / (2 * 2) / (2 * 2) / (2 * 2) = [- 7
Simplify and then evaluate: 5x2 - [3x-2 (2x-3) + 7X2], where x = 1 2．
The original formula = 5x2-3x + 2 (2x-3) - 7X2 = 5x2-3x + 4x-6-7x2 = - 2x2 + X-6,
When x = 1
When 2, the original formula = - 2 × (1)
2)2+1
2-6=-1
2+1
2-6=-6．
The inverse function of the function y = [1 + ln (x-1)] / 2 is
y=[1+ln(x-1)]/2
2y-1=ln(x-1)
e^(2y-1)=x-1
x=1+e^(2y-1)
Therefore, the inverse function is y = 1 + e ^ (2x-1)
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