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It is known that the system of equations 3x + 5Y = 2m + 1,4x + 2Y = 3m-2. When m is the value, the sign of X and Y is opposite and the absolute value is equal
When the sign of X and Y is opposite, the absolute value is equal
X and y are opposite numbers to each other, that is, x + y = 0
also
3X＋5Y＝2M＋1
4X＋2Y＝3M－2
When the two formulas are added, we get
7X＋7Y＝5M－1
That is, 5m-1 = 0
M = 1 / 5
Therefore, when m = 1 / 5, the sign of X and Y is opposite and the absolute value is equal
Given the equation system 3x + 2Y = m + 1 2x + y = M-1, when m is the value, the sign of X and Y is opposite and the absolute value is equal It is known that the system of equations 3x + 2Y = m + 1 2x + y = M-1, (1) When m is the value, the sign of X and Y is opposite and the absolute value is equal? (2) When m is a value, X is 1 greater than y?
There are many methods: the first one is to get x + y = 2x = (2x + y) - (x + y) = m-1-2 = m-3y = (2x + y) - 2x = m-1-2 (M-3) = - M + 5 (1) when M-3 = m-5, the signs of X and Y are opposite, and the absolute values are equal. 2) when M-3 = - M + 5 + 1, X is bigger than y by 1, and M = 4.5
On the absolute value of Y + 2x = 2x, y = 2m
According to "absolute value x = absolute value Y"
We know that x = y or - x = y
Therefore, in the first case, substituting x = y into x + 2m-1 = 2Y ①, 3x + y = 5m ② has
X + 2m - 1 = 2x, x = 2m - 1 (3)
3x + x = 5m, that is 4x = 5m (4)
Substituting (3) into (4) gives m = 4 / 3
In the same way, - x = y is substituted into x + 2m-1 = 2Y, 3x + y = 5m
M = 2 / 19
Let a = 2x ^ 2-3xy + y ^ 2-x + 2Y, B = 4x ^ 2-6xy + 2Y ^ 2-3x-y. find b-2a; if | x-2a | + (y + 3) ^ 2 = 0, and b-2a = a, find the value of A
B-2A=(4x^2-6xy+2y^2-3x-y)-2(2x^2-3xy+y^2-x+2y)=-x-5y
If ∵ |x-2a|+ (y+3) ^2=0, ∵ x=2a, y=-3, ∵ and B-2A=a, ∵ -x-5y=a, -2a+15=a, a=5
Let a = 2x ^ 2-3xy + y ^ 2-x + 2Y, B = 4x ^ 2-6xy + 2Y ^ 2-3x-y, if / x-2a / + (y + 3) ^ 2 = 0 and b-2a = a, let a = 2x ^ 2-3xy + y ^ 2-6xy + 2Y ^ 2-3x-y
The solution is - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2X - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x - 2x
If x = a, y = - 3, and - 2A = 2A, calculate the value of A
Is it - 2A + B = 2A
So - 4x? + 6xy-2y? + 2x-4y + 4x? - 6xy + 2Y? + 3x-y
=5x-5y
=5a+15=2a
a=-3
A=18-27+9+3-6=-3
Let a = 4x? - 6xy + 2Y? + 3x-y, B = 2x? - 3xy + y? - x + 2Y, if x = a, y = - 3, and a-2b = 2A, find the value of B
The solution a-2b = (4x? - 6xy + 2Y? + 3x-y) - 2 (2x? - 3xy + y? - x + 2Y) = (4x? - 4x? + (- 6xy + 6xy) + (2Y? - 2Y) + (3x + 2x) + (- y-4y) = 5x-5y = 5A + 15 = 2A 3A = - 15
Let a = 2x? - 3xy + y? - x + 2Y, B = 4x? - 6xy + 2Y? - 3x-y, if | x-2a | + (y + 3) A2 = 0, and - 2A + B = a, find a
Therefore, from - 2A + B = a, - x-5y = a, a = 5, x = 10, so a = 283
Let a = 2x squared - 3xy + y squared - x + 2Y, B = 4x's Square - 6xy + 2Y's square + 3x-y, if | x-2a | + (y + 3) square = 0, and b-2a = a, find a
|The square of (y + 2a) y = 0
∴x-2a=0
y+3=0
∴x=2a
y=-3
B-2a = (4x squared-6xy + 2Y squared + 3x-y) - 2 (2x squared-3xy + y squared-x + 2Y)
=4x²-6xy+2y²+3x-y-4x²+6xy-2y²+2x-4y
=5x-5y=a
∴10a+15=a
∴a=-5/3
Is it a or a
Let | x-2a | + (y = 3) be cubic = 0, a = 2x's square-3xy + Y's square-x = 2Y, B = 4x's square-6xy + 2Y's square-3x-y, and b-2a = a, find a Let | x-2a | + (y + 3) square = 0, a = 2x square - 3xy + y square - x = 2Y, B = 4x square - 6xy + 2Y square - 3x-y, and b-2a = a, find a
/x-2a/+(y+3)^2=0.
The sum square of absolute value is greater than or equal to 0, and the sum is equal to 0. If one is greater than 0, the other is less than 0, which is not true
So both are equal to zero
So x-2a = 0, y + 3 = 0
x=2a,y=-3
So a = 2 * (2a) ^ 2-3 * 2A * (- 3) + - 3 ^ 2-2a + 2 * (- 3) = 8A ^ 2 + 16A + 3
B=4*4a^2+36a+18-6a+3=16a^2+30a+21
B-2A=-2a+15
B-2a = a
So - 2A + 15 = a
A=5
A=8a^2+16a+3=200+80+3=283
I wish you every day to learn, come on!
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