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Given that the real number x, y satisfies the square root of x plus 4 times the square of Y equals 2x + 4Y-2?
Move 2x + 4Y-2 to the right, and x ^ 2-2x + 1 + 4Y ^ 2-4y + 1 = 0
(x-1)^2+(2y-1)^2=0
X = 1. Y = 1 / 2
X-2y = 0, the square root is 0
Let x.y satisfy {√ x-2y-3} + {3x + 2y-5} 2 = 0 to find the square root of x-4y
X-2y-3 = 0
3X+2Y-5=0
The solution is: x = 2, y = - 1 / 2
So X-4Y=0
So the square root of x-4y is zero
Given that the real numbers x, y, Z satisfy the square root of X + 4Y + the square of root - z = 2x + 4Y-2, find the square root of X + 2y-z
If the sum of squares and roots are greater than or equal to 0, then all of them will be 0-1 = 0,2y-1 = 0, - z = 1, y = 1 / 2, z = 0, so √ (x + 2y-z-z) = 0
Let the real number x, y satisfy (the square of X + the square of Y multiplied by 4 + 2x-4y + 2 = 0, what is the value of 2 y power of X + 2 x of Y? ditto
Convert x ^ 2 + 4 * y ^ 2 + 2x-4y + 2 = 0 into
(x+1)^2+(2y-1)^2=0
So x = - 1, y = 1 / 2
Substituting x ^ 2Y + y ^ 1 / 2 * 2x = (- 1) ^ 1 + (1 / 2) ^ 1 / 2 * (- 2) = - 1-2 ^ 1 / 2
Given that the real numbers x and y satisfy x 2 + 4Y 2 = 2x + 4Y-2, find the square root of x-2y Please, brothers and sisters, Xiao Xiao is in urgent need~
In this paper, we get the following results: x 2 + 4 y 2 = 2 x + 4 y - 2 y + 1 = 0 (x-1) 2 + (2y-1) 2 = 0 because (x-1) 2 and (2y-1) 2 are non negative numbers, so (x-1) 2 = 0, (2y-1) 2 = 0, then x = 1, 2Y = 1, x = 2Y, so √ (x-2y) = √ 0 = 0
Given the absolute value of [x + 3] 2 + [Y-7] = 7, find the value of [3x-2y] - 2 [2x + 3Y] Wrong, is equal to 0
The absolute value of [x + 3] power 2 + [Y-7] is 0
So x + 3 = 0, Y-7 = 0
x=-3,y=7
So the original formula = 3x-2y-4x-6y
=-x-8y
=3-8*7
=-53
Given that 2x-y of X + 3Y is equal to 2, find the algebraic expression x + 3Y divided by 4x-2y minus 4x + 12Y of 2x-y
2x-y of X + 3Y equals 2
(2x-y)/(x+3y)=2
The algebraic formula x + 3Y is 4x-2y, and 2x-y is 4x + 12Y
=2(2x-y)/(x+3y)-4(x+3y)/(2x-y)
=2*2-4*(1/2)
=4-2
=2
Given that x + 3Y is 2x-y = 2, find the value of the algebraic formula x + 3Y divided into 4x-2y - 2x-y divided by 4x + 12Y
X + 3Y in 4x-2y - 2x-y in 4x + 12Y
=2(2x-y)/(x+3y)-4(x+3y)/(2x-y)
=2*2-4*1/2
=4-2=2
Given that x + 3Y is 2x-y = 2, the algebraic expression x + 3Y is 4x-2y minus 2x-y is 4x + 12Y Detailed process
Let X in half = y in the third = z = K in half
Then x = 2ky = 3kz = 2K
X+3y-z: 2x-y+z=9k: 3K =1/3
Given 2x-y / x + 3Y = 2, find the value of the algebraic expression 4x-2y / x + 3Y minus 4x + 12Y / 2x-y
The answer is 2.4x-2y / x + 3Y = (2x-y / x + 3Y) times 2 = 4,4x + 12Y / 2x-y = (x + 3Y / 2x-y) times 4 = 1 / 2x4 = 2, so the algebraic expression is 4-2 = 2
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