C (OH & amp;# x2212;) ionized from water in both NaOH and Na2O2 solutions with a pH of 12, the former being less than the latter Why?

When NAOH is added to pure water at 25.d egree. C. and the pH of the solution is 11, the ratio of the OH-concentration ionized by NAOH to the OH-concentration ionized by water is?

25°C, PH is 11, so c (OH-)=10^-3mol/L, c (H+)=10^-11mol/L Because the OH- ionized by water is the same as H+(the ionization equation with water can be known), c (OH-)=10^-11mol/L ionized by water is 10^-11mol/L, because the ionized amount of water is more than 6 orders of magnitude different from that of alkali, so 10^-3mol/L can be regarded as all ionized by alkali. So, alkali ionization: water ionization =10^-3:10^-11=10^8:1

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