What is the valence of iron and oxygen in Fe3O4?

What is the valence of iron and oxygen in Fe3O4?

Fe3O4 is short for FeO.Fe2O3!
So one Fe is +2 valence,
2 For +3
Take average valence state +8/3 for calculation!
Are you a junior high school student? When I went to junior high school, I also asked the teacher this question. He said he wouldn't take the exam, but he did n' t tell me, so he always remembered. Ha ha!

Fe3O4 is short for FeO.Fe2O3!
So one Fe is +2,
2 For +3
Take average valence state +8/3 for calculation!
You're in junior high, right? When I went to junior high school, I also asked the teacher this question. He said he wouldn't take the exam, but he did n' t tell me, so he always remembered. Ha ha!

Fe3O4 was the abbreviation of FeO, Fe2O3!
Therefore, there is a Fe price of +2,
+3 For 2
The average price state was +8/3!
Are you a junior high school student? I asked this question to my teacher when I was in middle school. He said he wouldn't take the exam, but he did n' t tell me, so he always remembered. Haha!

ON THE FORMATION OF IRON TETRAOXIDE BY IRON COMBUSTION IN OXYGEN The iron is burned in oxygen to form iron trioxide, and the mass ratio between the reactants in the reaction and the products is calculated ON THE FORMATION OF IRON TRIOXIDE BY IRON COMBUSTION IN OXYGEN The iron is burned in oxygen to form iron trioxide, and the mass ratio between the reactants in the reaction and the products is calculated

3Fe+2O2= ignition = Fe3O4
168 64 232
M iron: m oxygen: m iron tetroxide =168:64:232=21:8:29
Therefore, in the reaction in which iron is burned in oxygen to form iron trioxide, the mass ratio between the reactant iron and oxygen and the resultant iron trioxide is 21:8:29.

3Fe+2O2= ignition = Fe3O4
168 64 232
M iron: m oxygen: m iron tetroxide =168:64:232=21:8:29
Therefore, in the reaction in which iron is burned in oxygen to form iron trioxide, the mass ratio of reactant iron to oxygen and resultant iron trioxide is 21:8:29.