A 40 cm long,20 cm wide,30 cm high (measured from the inside) rectangular glass tank with a water depth of 18 cm. Now an iron ball is completely immersed in the water and the water surface rises 25Cm, find the volume of iron ball A 40 cm long,20 cm wide,30 cm high (measured from inside) rectangular glass tank with a water depth of 18 cm. Now an iron ball is completely immersed in the water and the water surface rises 25Cm, find the volume of iron ball

A 40 cm long,20 cm wide,30 cm high (measured from the inside) rectangular glass tank with a water depth of 18 cm. Now an iron ball is completely immersed in the water and the water surface rises 25Cm, find the volume of iron ball A 40 cm long,20 cm wide,30 cm high (measured from inside) rectangular glass tank with a water depth of 18 cm. Now an iron ball is completely immersed in the water and the water surface rises 25Cm, find the volume of iron ball

Volume of iron ball = volume of water tank rising
40*20*(25-18)=5600Cm^3

Volume of iron ball = volume of water cylinder rising
40*20*(25-18)=5600Cm^3

In a glass tank that was 25 cm long and 20 cm wide, there was a rectangular iron block that was 10 cm long. At this time, the water depth was 15 cm. If the iron block was removed from the tank, how many centimeters was the water depth in the tank? In a glass cylinder of 25 cm in length and 20 cm in width, there is a rectangular iron block of 10 cm in length. At this time, the water depth is 15 cm. If the iron block is removed from the cylinder, how much is the water depth in the cylinder?

25×20×15-10×10×10
=7500-1000
=6500(Cc)
6500÷(25×20)
=6500÷500
=13(Cm)
Answer: The water depth in the cylinder is 13 cm.