Under certain conditions, the chemical equation for the reaction of ethylene and propylene in the molar ratio of 1:1 to produce polyethylene is the solution.

Under certain conditions, the chemical equation for the reaction of ethylene and propylene in the molar ratio of 1:1 to produce polyethylene is the solution.

Under one condition, when the ratio of ethylene to propylene is 1:1, there are two forms of polymerization, but no matter how the polymerization is added, the double bond between ethylene and propylene is opened and extends to both ends.
Aggregation results are as follows

Under one condition, when the ratio of ethylene to propylene is 1:1, there are two forms of addition polymerization, but no matter how the polymerization is added, the double bond of ethylene and propylene is opened and extends to both ends.
The polymerization result is as follows

Under one condition, when the ratio of ethylene to propylene is 1:1, there are two forms of addition polymerization, but no matter how to add polymerization, the double bond between ethylene and propylene is opened and extends to both ends.
Aggregation results are as follows

Some reaction chemical equations and reaction types of propylene and ethylene. I.(1) Reaction of propylene with bromine water (2) Propylene fully burned (3) Propylene polymerization (4) Reaction of ethylene with HBr (5) Reaction of ethylene with water 2. After the complete combustion of 0.5mol of a hydrocarbon, the gas is introduced into the excess lime water to form 100g of white precipitate. If the same mass of the hydrocarbon is taken after the complete combustion, the whole product is introduced into a drying tube containing sufficient sodium peroxide. After the effect is sufficient, the drying tube is increased by 30g. III. If the relative molecular weight of a hydrocarbon is 84, the hydrocarbon can make bromine water fade, and the carbon atoms in the molecule are all on the same plane, the structure formula of the hydrocarbon is ______, and its name is ______.

One (1) CH3CH=CH2+Br2==CH3CHBr-CH3(2) CH3CH=CH2+4O2=3CO2+2H2O (3) CH3CH=CH2=CH3(CH-CH2) n is a catalyst at high temperature and high pressure.(4) CH2=CH2+Br2=CH2BrCH3 or the white precipitate of the formation of CH3CH2Br (5) CH2=CH2+H2O=CH2CH2OH (ethanol) is CACO3...