The mass of the brominated carbon tetrachloride solution was increased by 8.4 g after the mixture of 11.2 L (standard condition) ethylene and ethane was introduced into a sufficient amount of brominated carbon tetrachloride solution. A mixture of 11.2 L (standard condition) ethylene and ethane is introduced into a sufficient amount of bromine-based carbon tetrachloride solution. After a sufficient reaction, the mass of bromine-based carbon tetrachloride solution is increased by 8.4 g to obtain the mass ratio of ethylene to ethane in the raw gas mixture. A mixture of 11.2 L (standard condition) ethylene and ethane is introduced into a sufficient amount of bromine-based carbon tetrachloride solution. After the reaction, the mass of bromine-based carbon tetrachloride solution is increased by 8.4 g to obtain the mass ratio of ethylene to ethane in the raw gas mixture.

The mass of the brominated carbon tetrachloride solution was increased by 8.4 g after the mixture of 11.2 L (standard condition) ethylene and ethane was introduced into a sufficient amount of brominated carbon tetrachloride solution. A mixture of 11.2 L (standard condition) ethylene and ethane is introduced into a sufficient amount of bromine-based carbon tetrachloride solution. After a sufficient reaction, the mass of bromine-based carbon tetrachloride solution is increased by 8.4 g to obtain the mass ratio of ethylene to ethane in the raw gas mixture. A mixture of 11.2 L (standard condition) ethylene and ethane is introduced into a sufficient amount of bromine-based carbon tetrachloride solution. After the reaction, the mass of bromine-based carbon tetrachloride solution is increased by 8.4 g to obtain the mass ratio of ethylene to ethane in the raw gas mixture.

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Equation for the reaction of acetaldehyde with carbon tetrachloride solution of bromine? The equation for acetaldehyde to discolour bromine water involves water, but what is the mechanism by which it discolorizes bromine-based carbon tetrachloride solutions?

CH3CHO + Br2= CH3COBr + HBr
CH3CHO + Br2= CH2BrCOH + HBr
The first product is acetyl bromide and the second is α-bromoacetaldehyde.