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What is the 2nd power of 1997 minus 1996 by 1997 How to write it?
(1997^2-1996*1998)/1997
=(1997^2-(1997-1)*(1997+1))/1997
=1/1997.
Given that m =1996+1995*1996+1995*1996 2+...+1995*1996 1994 power +1995*1996 1995 power, n =1996 power, then the relationship between m and n is Am=n+1995 B m=n+1996 C m=n D m=n-1996
M-n =1996+1995*1996+1995*1996 2+...+1995*1996's 1994 power +1995*1996's 1995 power -1996 power =1996+1995*1996+1995*1996 2+...+1995*1996's 1994 power +1995*1996's 1995 power =1996+1995*1...
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