What is the 2003 power of 3 minus the 2002 power of 5 by 3, plus the 2001 power of 6 by 3!

What is the 2003 power of 3 minus the 2002 power of 5 by 3, plus the 2001 power of 6 by 3!

3^2003-5*3^2002+6*3^2001 =9*3^2001-15*3^2001+6*3^2001 =0

If (a+b)2001=-1,(a-b)2002=1, then the value of a2003+b2003 is () A.2 B.1 C.0 D.-1

(A+b)2001=-1 a+b=-1;
(A-b)2001=1 a-b=1 or a-b=-1.
Therefore, the equations can be formed
A+b=−1
A−b =1 or
A+b=−1
A−b =−1,
The solutions of the equations are
A =0
B=−1 or
A =−1
B=0
A2003+b2003=-1
Therefore, D.

Elden Ring Premiere

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