Can you find the value of (x-1)(99th power of x +98th power of x +97th power of x +.+x+1)? It all starts with a simple situation. Calculate the following values separately (A-1)(a+1)= (A-1)(a squared +a+1)= (A-1)(a cube + a square + a +1)= Thus we can get: (A-1)(99th power of a+97th power of 98th power of a+2+...+a+1)= Please use the above conclusions to complete the following calculations (1)99Th power of a+98th power of a+97th power of 2+...+2+1 (2)(-2)50Th power +(-2)49th power +(-2)48th power +...+(-2)+1 What I want is my answer, not online!

Calculate the following values separately
(A-1)(a+1)= a2-1
(A-1)(a squared +a+1)= a3-1
(A-1)(a cube + a square + a +1)= a^4-1
Thus we can get:
(A-1)(99th power of a+98th power of a+97th power of 2+...+a+1)=a^100-1
Please use the above conclusions to complete the following calculations
(1)99Th power of a+98th power of a+97th power of 2+...+2+1=(a^100-1)/(a-1)
(2)(-2)50Th power +(-2)49th power +(-2)48th power +...+(-2)+1
=[(-2)^51-1]/[-2-1]
=(2^51+1)/3

Can you find the value of (a-1)(a's 99th power +a's 98th power +2's 97th power +...+a+1)? First, calculate the values of (A-1)(a+1)= (A-1)(square of a+a+1)= (A-1)(a cube + a square + a +1)= We can get: (A-1)(99th power of a+97th power of 98th power of a+2+...+a+1)= Please use the above conclusions to complete the following calculations 199Th power of 2+2198th power of 2+2197th power of +.

(A-1)(a+1)=a2-1(a-1)(a squared +a+1)=a3-1(a-1)(a cube +a squared +a +a +1)=a4-1 So we can get:(a-1)(a 99th power +a 98th power +2 97th power +...+a+1)=a 100th power -199th power +2 198th power +2...

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