In the old algorithm of rational number, we define the new operation "(+)" as follows: When a > or =b, a (+) b=b×b; when a

In the old algorithm of rational number, we define the new operation "(+)" as follows: When a > or =b, a (+) b=b×b; when a

1(+) X =1
3(+) X=x2=4
Original formula=1×2-4=-2

If for any nonzero rational number a, b, the defined operation "⊙" is as follows: A⊙B=B÷A-1, then what is the result of (-4)⊙3⊙(-2)? If for any nonzero rational number A, B, the defined operation ⊙ is as follows: A⊙B=B/A-2, then what is the value of (-6)⊙2? What is the value of (-6)⊙2⊙1?

If for any nonzero rational number a, b, the defined operation "⊙" is as follows: A⊙B=B÷A-1, then the result of (-4)⊙3⊙(-2) is 1/7,
If for any nonzero rational number A, B, the defined operation ⊙ is as follows: A⊙B=B/A-2, then the value of (-6)⊙2 is (-7/3),
(-6) The value of ⊙2⊙1 is (-17/7)