Here is a regular set of numbers: 1, 2, 4, 8, 16 , then the number 2005 is () A. 22005 B. 22004 C. 22006 D. 22003

∵1=20，2=21，4=22，…
The number of 2005 is 22004
Therefore, B

The following set of numbers in regular order: 1,2,4,8,16 The number of 2012 should be [ A. 2 to the 2012 power B.2 to the 2012 power - 1 C.2 to the 2011 power D

1=2^(1-1)=2^0
2=2^(2-1)=2^1
4=2^(3-1)=2^2
8=2^(4-1)=2^3
16=2^(5-1)=2^4
.
The general formula can be deduced as: 2 ^ (n-1)
So the number of 2012 is n = 2012, that is, the answer is 2 ^ (2012-1) = 2 ^ 2011, and the answer is C

0,1,4,15,56 () to find the law

The law of 0,1,4,15,56, (209) is
1*4-0=4
4*4-1=15
15*4-4=56
56*4-15=209
209*4-56=780

Fill in the numbers: 0, 1, 4, 15, 56______ .

According to the analysis, it can be concluded that,
56×4-15=209，
Validation: 15 × 4-4 = 56;
So the answer is: 209

What is the next number in the order of 0.1 4 15 56 Using Fibonacci sequence and other laws to solve it

Use a (n) to represent the sequence
a(0)=0,a(1)=1,a(2)=4,a(3)=15,a(4)=56
a(n+1)=4a(n)-a(n-1)
a(5)=4*56-15=209

What's the next number? Why?

Answer: 209
（1＋4）×3－0＝15
（4＋15）×3－1＝56
（15＋56）×3－4＝209

1.4.15.56 (209) what's the rule of the number problem?

1×4＝0＋4
4×4＝1＋15
15×4＝4＋56
56×4＝15＋（209）

Who knows the rule of finding numbers 7,8,10,13,18 (), what are the two numbers after?

7+1=8
8+2=10
10+3=13
13+5=18
1 2 3 5
3=2+1
5=3+2
therefore
It should be 18 + (5 + 3) = 26
And 26 + (8 + 5) = 39

The first question: 4.7.8.4.6.13.4.5.18. (?). (?). The second question: 2.4.10.28.82

In the first question, the first number is 4, the second number is - 1 each time, the third number is + 5 each time, so fill in the second question (4, 4, 23) with the previous number * 3-2 each time, so fill in (244, 730)

Fill in the numbers 4,5,8,10,12, (), (), ()

This problem is calculated by skipping:
1.4, 8 and 12 are all + 4, so 5 and 10 (the multiple of 5) can be skipped, so the seventh number is 16
Therefore, we can get the number of + 2, 4, and 5 respectively
So the last three spaces are 15, 16 and 20
Thank you for your question and wish you progress in your studies

Here is a regular set of numbers: 1, 2, 4, 8, 16 , then the number 2005 is () A. 22005 B. 22004 C. 22006 D. 22003