Generally speaking, the speed of cars is faster than that of bicycles, and the speed of bicycles is faster than that of people. When judging the speed of cars, bicycles and people, is it determined by the length of exercise distance or the amount of exercise time? Give your opinion

Generally speaking, the speed of cars is faster than that of bicycles, and the speed of bicycles is faster than that of people. When judging the speed of cars, bicycles and people, is it determined by the length of exercise distance or the amount of exercise time? Give your opinion

Fine! A certain length of time or a certain distance is longer than the time used

The speed of an aircraft is 20 times that of a car, while the speed of a bicycle is 1 / 5 of that of a car, and the speed of walking is 1 / 2 of that of a bicycle. If the speed of a car is a km / h, the speed of an aircraft is () km / h, the speed of a bicycle is () km / h, and the speed of walking is () km / h

20a 1/5a 1/10a

Someone travels for 22 days by train, 1 / 3 by car and 1 / 4 by bike. The speed of bicycle is 1 / 8 of that of train and 1 / 4 of that of car, Supplementary question: how many days by train, car and bike?

If x days are taken by train, y days by car and Z days by bike, and the total distance is s, then
X+Y+Z=22 ,8/Z=1/X=2/Y,
The solution is x = 2
Y=4
Z=16
A: 2 days by train, 4 days by car and 16 days by bike

What is the speed of walking, bicycle and car

People usually walk at a speed of 4 ~ 7 km / h. if they walk fast, they may walk 10 km / h. if they walk fast, they can reach 15 km / h
The speed of ordinary bicycles is 16-18km / h, and if you ride faster, it will be 20km / h
The speed of the car is not easy to talk about. It can range from zero to hundreds of hours

The normal speed of the train from station a to station B is 60 km / h. a train left station a 5 minutes late for some reason. The driver increased the speed to 72 km / h. as a result, it arrived at station B on time. What is the distance between the two stations? What is the normal travel time of the train from a to B? Answer questions in a scientific way,

The normal time is h hours and the distance between the two stations is s km 1) 60H = s delay time: 5 / 60 = 1 / 12 hours 2) 72 (h-1 / 12) = S1), 2) the formula 72 (h-1 / 12) = 60h72h-6 = 60h72h-60h = 612h = 6h = 0.5 (H) 60H = s60x0.5 = S30 = s, that is, s = 30 (km), so the normal time is 0.5 hours and the two stations

The normal running speed of the train from station a to station B is 60 km / h The normal running speed of the train from station a to station B is 60 km / h. for some reason, an existing train left station a 5 minutes late, and the driver raised the speed to 72 km / h. as a result, it just arrived at station B on time. What is the distance between stations a and B?

60*(72*(1/12)/(72-60))=30km