Please write the function expression passing through point (1,1) 1. Please write a function that passes through point (1, 1). The analytical formula y = negative x + 2 (a little more)

y=ax-a
A is any number that is not 0, that is, a is not equal to 0

Is the function correspondence a function expression?

yes

Write the function expression according to the given function image

The function expression can be obtained through the fitting function of Excel

Calculation by formula 1.〔（3a+b）（3a-b）〕 ² 2.（2x+y） ² （2x-y） ² 3.（5m+2n） ²— （5m-2n） ² 4.（-5x+3y-2z） ² 5.（-a-b+3） ² 6.（-3x-5y） ² 7.（-2a+3b-5c）（-2a-3b+5c） 8.（3m-4n+2）（-3m-4n-2） 9. Find x if x + one in x = 5 ²+ x ² One third of the value 10. Find a when A-B = 7 and ab = 2 are known ²+ b ² Value of 11. Known x ²- 8x+y ²+ 6y + 25 = 0 find the values of X and y

1.[（3a+b）（3a-b）]^2
=[(3a)^2 - b^2]^2
=(9a^2 - b^2)^2
=81a^4 - 18a^2b^2 + b^4
2.（2x+y)^2（2x-y)^2
=[(2x+y)(2x-y)]^2
=[(2x)^2 - y^2]^2
=(4x^2 - y^2)^2
=16x^4 - 8x^2y^2 + y^4
3.（5m+2n)^2 —（5m-2n)^2
=[(5m+2n)+(5m-2n)][(5m+2n)-(5m-2n)]
=(10m)(4n)
=40mn
4.（-5x+3y-2z)^2
=25x^2 - 15xy + 10xz - 15xy + 9y^2 - 6yz + 10xz - 6yz + 4z^2
=25x^2 - 30xy + 20xz + 9y^2 - 12yz + 4z^2
5.（-a-b+3)^2
=a^2 + ab - 3a + ab + b^2 - 3b - 3a - 3b + 9
=a^2 + 2ab - 6a + b^2 - 6b + 9
6.（-3x-5y） ²
=9x^2 + 30xy + 25y^2
7.（-2a+3b-5c）（-2a-3b+5c）
=[-2a+(3b-5c)][-2a-(3b-5c)]
=(-2a)^2 - (3b-5c)^2
=4a^2 - 9b^2 + 30bc - 25c^2
8.（3m-4n+2）（-3m-4n-2）
=-(3m-4n+2)(3m+4n+2)
=-[(3m+2)-4n][(3m+2)+4n]
=-[(3m+2)^2 - (4n)^2]
=-9m^2 - 12m - 4 + 16n^2
9.[x+(1/x)]^2 = x^2 + 2 + (1/x)^2 = 25
x^2 + 1/x^2 = 25-2=23
10.a^2 + b^2 = (a-b)^2 - 2ab = 7^2 - 2 × 2=49-4=45
11.x^2-8x+y^2+6y+25=0
(x^2-8x+16)+(y^2+6y+9)=0
(x-4)^2 + (y+3)^2=0
∵ (x-4) ^ 2 and (y + 3) ^ 2 are constant ≥ 0
∴x-4=0 ,y+3=0
x=4 ,y=-3

What is the integrity of mathematical function formula?

1、 Four operation rules of function, limit and continuous limit: Lim f (x) = a, Lim g (x) = B (x) Lim [f (x) g (x)] = Lim f (x) Lim g (x) = Alim f (x) g (x) = Lim f (x) Lim g (x) = abLIM f (x) / g (x) = Lim f (x) / Lim g (x) = A / b (b) 2. Commonly used equivalent formula x

Find all formulas of higher one mathematical function

Trigonometric function formula
Two angle sum formula
sin(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-sinBcosA
cos(A+B)=cosAcosB-sinAsinB cos(A-B)=cosAcosB+sinAsinB
tan(A+B)=(tanA+tanB)/(1-tanAtanB) tan(A-B)=(tanA-tanB)/(1+tanAtanB)
ctg(A+B)=(ctgActgB-1)/(ctgB+ctgA) ctg(A-B)=(ctgActgB+1)/(ctgB-ctgA)
Angle doubling formula
tan2A=2tanA/(1-tan2A) ctg2A=(ctg2A-1)/2ctga
cos2a=cos2a-sin2a=2cos2a-1=1-2sin2a
Half angle formula
sin(A/2)=√((1-cosA)/2) sin(A/2)=-√((1-cosA)/2)
cos(A/2)=√((1+cosA)/2) cos(A/2)=-√((1+cosA)/2)
tan(A/2)=√((1-cosA)/((1+cosA)) tan(A/2)=-√((1-cosA)/((1+cosA))
ctg(A/2)=√((1+cosA)/((1-cosA)) ctg(A/2)=-√((1+cosA)/((1-cosA))
Sum difference product
2sinAcosB=sin(A+B)+sin(A-B) 2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)-sin(A-B) -2sinAsinB=cos(A+B)-cos(A-B)
sinA+sinB=2sin((A+B)/2)cos((A-B)/2 cosA+cosB=2cos((A+B)/2)sin((A-B)/2)
tanA+tanB=sin(A+B)/cosAcosB tanA-tanB=sin(A-B)/cosAcosB
ctgA+ctgBsin(A+B)/sinAsinB -ctgA+ctgBsin(A+B)/sinAsinB
Sum of the first n items of some series
1+2+3+4+5+6+7+8+9+…+n=n(n+1)/2 1+3+5+7+9+11+13+15+…+(2n-1)=n2
2+4+6+8+10+12+14+…+(2n)=n(n+1) 12+22+32+42+52+62+72+82+…+n2=n(n+1)(2n+1)/6
13+23+33+43+53+63+…n3=n2(n+1)2/4 1*2+2*3+3*4+4*5+5*6+6*7+…+n(n+1)=n(n+1)(n+2)/3
Sine theorem a / Sina = B / SINB = C / sinc = 2R note: where R represents the radius of the circumscribed circle of the triangle
Cosine theorem B2 = A2 + c2-2accosb note: angle B is the angle between edge a and edge C
Arc length formula L = a * r a is the radian number of circle center angle R > 0 sector area formula s = 1 / 2 * L * r
Multiplication and factorization A2-B2 = (a + b) (a-b) A3 + B3 = (a + b) (a2-ab + B2) a3-b3 = (a-b (A2 + AB + B2)
Trigonometric inequality | a + B ≤ | a | + | B | A-B ≤ | a | + | B | a | ≤ B-B ≤ a ≤ B
|a-b|≥|a|-|b| -|a|≤a≤|a|
Solution of quadratic equation of one variable - B + √ (b2-4ac) / 2A - B - √ (b2-4ac) / 2A
Relationship between root and coefficient X1 + x2 = - B / a X1 * x2 = C / a note: Weida theorem
Discriminant
B2-4ac = 0 note: the equation has two equal real roots
B2-4ac > 0 note: the equation has two unequal real roots
b2-4ac

Please write the function expression passing through point (1,1) 1. Please write a function that passes through point (1, 1). The analytical formula y = negative x + 2 (a little more)