34. It is known that the market demand function of a commodity is QD = 30-p and the market supply function is QS = 3p-10. If a tax reduction is implemented for the commodity, the market equilibrium price after tax reduction () A. Equal to 10 b, less than 10 C, greater than 10 d, less than or equal to 10

34. It is known that the market demand function of a commodity is QD = 30-p and the market supply function is QS = 3p-10. If a tax reduction is implemented for the commodity, the market equilibrium price after tax reduction () A. Equal to 10 b, less than 10 C, greater than 10 d, less than or equal to 10

Select B. if the tax is reduced for producers, the cost will be reduced, so that the supply curve will move to the right; If the tax cut for consumers also shifts the demand curve to the right, the result is that the new equilibrium price is lower than the original equilibrium price (10)

Given that the demand function of a product is QD = 60-2p and the supply function is QS = - 30 + 3P, find the demand elasticity and supply elasticity of the equilibrium point

(1) Supply and demand equilibrium conditions: QD = QS, 60-2p = - 30 + 3P, equilibrium point: P = 18, substitute QD = QS = 24;
(2) According to the definition of demand point elasticity: ed = P / QD · dqd / DP = 18 / 24 · (- 2) = - 3 / 2;
Similarly, according to the definition of supply point elasticity: ES = P / QS · DQS / DP = 18 / 24 · 3 = 9 / 4

The market demand function is QD = 12-2p, and the supply function is QS = 2p. What is the equilibrium price and output when the market demand curve moves 2 units to the right

Qd=12-2P +2 Qs=2P
P=3.5 Q=7

Given the demand function and supply function, how to find the price elasticity and supply elasticity of the equilibrium point It is known that the demand function of a commodity is QD = 60-2p and the supply function is QS = 30 + 3p. Find the demand elasticity and supply elasticity of the equilibrium point The answer is: the demand elasticity of the equilibrium point ed = 1 / 4, and the supply elasticity ES = 3 / 8 How is the detailed solution?

Elasticity refers to DQ / DP * P / Q
The latter P and Q refer to equilibrium price and equilibrium output

How to set the quadratic function expression in the application problem? For some practical problems, we need to set y = ax ²＋ BX has some problems, but also set y = ax ²＋ C why? How? Can you give me some examples? I'm stupid

Let y = ax ²＋ BX, the image crosses the origin, and the axis of symmetry is generally not the Y axis;
Let y = ax ²＋ When C, the symmetry axis of the image is the y-axis, and generally it does not pass the origin (unless C = 0, it also passes the origin)

Find function expression Given that the function f (x) f '(x) = KF (x) + b k < 0 f (0) = 0 f' (0) = 3 is that the asymptote of the tangent slope 3 F (x) at (0, 0) point is y = 2, can we find f (x)

Because f '(x) = KF (x) + B, and f (0) = 0, f' (0) = 3
So 3 = f '(0) = KF (0) + B = b
Because the asymptote of F (x) is y = 2, when x approaches positive infinity or negative infinity, f '(x) = 0 and f (x) = 2
Bring in F '(x) = KF (x) + 3
K = - 3 / 2 can be obtained
So f '(x) = - 3 / 2 * f (x) + 3
So we can write dy / DX = 3-3y / 2
So dy / (3-3y / 2) = DX
By integrating on both sides, - 2ln (3-3y / 2) / 3 = x + C (C is a constant)
Because f (0) = 0,
So C = - (2ln3) / 3
So - 2ln (3-3y / 2) / 3 = x - (2ln3) / 3
So ln (3-3y / 2) = - 3x / 2 + Ln3
So e ^ (- 3x / 2 + Ln3) = 3-3y / 2
So y = 2-2e ^ (- 3x / 2 + Ln3) / 3
Checking calculation f '(x) = - 2E ^ (- 3x / 2 + Ln3) / 3 * (- 3 / 2) = e ^ (- 3x / 2 + Ln3)
-3/2 *f(x)+3=-3/2 *（2-2e^(-3x/2 +ln3)/3）+3=e^(-3x/2 +ln3)
f（0）=2-2e^(ln3)/3=0
Because f '(x) = e ^ (- 3x / 2 + Ln3)
So f '(0) = e ^ (Ln3) = 3
So the function y = 2-2e ^ (- 3x / 2 + Ln3) / 3
Meet the condition f '(x) = KF (x) + b k ＜ 0
f（0）=0
f’（0）=3
The asymptote of F (x) is y = 2