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What is the domain of the function y = ln (x-1)?
The domain of function y = ln (x-1) must meet:
x-1>0
x>1
Then the domain is x > 1
Or expressed as (1, + ∞)
What is the domain of the function y = ln (x-1)?
Solve the inequality X-1 > 0 and get x > 1,
The domain of the function y = ln (x-1) is (1, + ∝)
The domain of the function y = ln (x-1) is () A. （1，2） B. [1，+∝） C. （1，+∝） D. （1，2）∪（2.，+∝）
Solve the inequality X-1 > 0 and get x > 1,
Therefore, C
Let f (x) = ln [(1 + x) / (1-x)], then the definition field of function g (x) = f (x / 2) + F (1 / x) is? Detailed process Simultaneous - 1 ＜ X / 2 ＜ 1 and not equal to 0, - 1 ＜ 1 / X
(1 + x) / (1-x) > 0 and not equal to 1, the solution is - 1 ＜ x ＜ 1 and X not equal to 0. Simultaneous - 1 ＜ X / 2 ＜ 1 and not equal to 0, - 1 ＜ 1 / X
Function f (x) = 1 ln(x+1)+ The domain of 4 − X2 is __
from
x+1＞0
x+1≠1
4−x2≥0 ， The solution is: - 1 ＜ x ≤ 2, and X ≠ 0
‡ function f (x) = 1
ln(x+1)+
The domain of 4 − X2 is {x | - 1 ＜ x ≤ 2, and X ≠ 0}
So the answer is: {x | - 1 ＜ x ≤ 2, and X ≠ 0}
Function f (x) = √ X-1 × The domain of Ln (2-x) is
x-1≥0
2-x＞0
So the solution set
[1,2)
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