If the top angle of an isosceles triangle is x degrees, then the angle between the high line on the waist and the bottom edge is______ Degree

∵ the angle between the height of one waist and the bottom of an isosceles triangle is equal to half of the top angle,
The angle between the high line on the waist and the bottom edge is X
2 degrees
Therefore, fill in X
2．

The angle between the height and the base of an isosceles triangle is equal to half of the vertex angle The angle between the height of the waist and the base of an isosceles triangle (not an equilateral triangle) is equal to half of the top angle. Why? Please prove it

Draw a picture by yourself
If a is a fixed point and BC is a base edge, then the top angle of isosceles triangle is divided into two equal small angles by making a height ad at the bottom edge
Height from anchor B, be, then be is perpendicular to AC
Then half of the top angle, that is, the angle DAC = 90 degrees - angle C
At the same time, angle EBC = 90 degrees - angle c (angle EBC is the angle between the height of a waist and the bottom edge)
The two angles are equal
The proof is complete

Proof: isosceles acute angle triangle, the angle between the waist height and the base is equal to half of the vertex angle

Prove: as shown in the figure: △ ABC is isosceles acute triangle, ab = AC, BD is the height of waist AC
Pass through point a as AE ⊥ BC at point E,
∴∠EAC+∠C=90°，
∵BD⊥AC，
∴∠DBC+∠C=90°，
∴∠DBC=∠EAC，
∵AB=AC，AE⊥BC，
∴∠EAC=1
2∠BAC，
∴∠DBC=1
2∠BAC．

The angle between the height of the waist and the base of an isosceles triangle is equal to half of the top angle!

It is known that: the triangle ABC is an isosceles triangle, ab = AC, BD is the height verification on the AC side; the angle DBC = 1 / 2 angle BAC proves: through a as AE vertical BC, let AE intersect BD at the point h, because AB = AC, so the angle EAC = angle EAB = 1 / 2 angle BAC angle AEC = 90 degrees, so the angle ACE + angle EAC = 90 degrees, because BD is the high angle on the AC side with BDC = 90 degrees

Given that the angle between the height of one waist and the other waist of an isosceles triangle is 45 degrees, find the degree of the vertex angle of the isosceles triangle

There are two answers:
Because it is high, there is an angle of 90 degrees. Because the included angle is 45 degrees, the complementary angle with the top angle is 45 degrees. Then the degree of the vertex angle is 135 degrees
Because it is high, there is an angle of 90 degrees. Because the included angle is 45 degrees, the sum of the inner angles of the triangle is 180 degrees. Therefore, the top angle is 45 degrees

If the angle between the height of one waist and that of the other is 45 degrees, the degree of the vertex angle is a process

∵ the angle between the height on one waist and the other is 45 degrees
The bottom angle of the triangle is 180-90-45 = 45 degrees
∵ this is an isosceles triangle
The sum of the two bottom angles is 90 degrees
The vertex angle is 180-90 = 90 °

Of the three angles of an isosceles triangle, the top angle is 45 degrees. How many degrees is one of its base angles?

180°-45°=135°
135°÷2=67.5°

The top angle of an isosceles triangle is 70 degrees, and each base angle is___ Degree

（180°-70°）÷2，
=110°÷2，
=55°；
A: each base angle is 55 degrees;
So the answer is: 55

If the top angle of an isosceles triangle is three times the base angle, what are the degrees of its top angle and base angle?

The base angle is 36 degrees and the top angle is 108 degrees
180 / (3 + 2) = 36 degrees
36 degrees × 3 = 108 degrees

In an isosceles triangle of grade 4 mathematics in primary school, the degree of a base angle is twice that of the top angle. It needs a process to find the degree of a base angle

In an isosceles triangle, the degree of a base angle is twice that of the top angle
As you can see, the ratio of the base angle to the top angle of this triangle is 1:2
Also know: an isosceles triangle has a top angle, two base angles, the two base angles are equal
The sum of the interior angles of a triangle is 180 degrees
We can divide the 180 ° into (1 + 2 + 2) parts
We can work out how many degrees a portion is
1 + 2 + 2 = 5 (copies)
180÷5＝36°
The bottom corner takes up two parts like this: what's the degree of two?
36×2＝72°
The top corner accounts for such a share. What is the degree of one share?
1×36＝36°
A: the base angle is 72 ° and the apex angle is 36 °
In order to test: this method to find the answer is right?
This method can be used: 36 + 72 + 72 = 108 + 72 = 180
Obviously, it is
That's it,

If the top angle of an isosceles triangle is x degrees, then the angle between the high line on the waist and the bottom edge is______ Degree